1000 ml of solution is made in water by dissolving 90 gram of monobasic acid (mol. wt = 60 ). the density of solution is 0.99 calculate the molarity and normality of solution.
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Answer:
Consider 1000 mL of water.
Mass of 1000 mL of water =1000×1=1000g
No. of moles of water =
18
1000
=55.5
Molarity =
Volume in litre
No. of moles of water=
1 ×55.5 =55.5M
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