1000 small drops or water each word radius r having charge q form a large spherical drop the electric potential of large drop at its surface is higher than the potential at surface of small drops by
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Answer:100 times the initial potential.
Explanation:
Let initial potential be V = kq/r.
Volume of 1000small drops = 1000.4/3.pie.r^3
Let the radius of big drop be R so
R = 10r
New potential = k1000q/10r = 100V
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