Question

1000 soldiers confined in Kaala-Qila can survive for 13 days with the remaining stock of cereals if they consume half-meal-a-day. How many soldiers may survive for 78 days if they consume full-meal-a-day but have 3 times the stock of cereals?

Answer 1

Answer:

250 soldiers may survive for 78 days if they consume full-meal-a-day but have 3 times the stock of cereals.

Given:

1000 soldiers confined in Kaala-Qila can survive for 13 days with the remaining stock of cereals if they consume half-meal-a-day.

To find:

How many soldiers may survive for 78 days if they consume full-meal-a-day but have 3 times the stock of cereals.

Solution:  

1000 soldiers can survive half a meal for 13 days.

Hence 500 soldiers can survive full meal for 13 days.

Hence there are 500 $\times$ 13 = 6500 meals in total.

When the stock is tripled, say 6500$\times$3 = 19500 meals are available to be consumed by 78 days.

The number of soldiers $= \frac{19500}{6500}$ = 250 Soldiers.