₹ 10000 for 2 years at 11% per annum compounded annually
Answers
Answered by
57
Principal,p=Rs 10000
Rate,r=11%
Time,n=2 years
=p(1+R/100)whole 2
=10000(1+11/100)whole 2
=10000(100+11/100)whole 2
=10000(111/100)whole 2
=10000*111/100*111/100
Now do cancelletion.
Zero will be cancelled
=1*111*111
=111*111
=12321
Therefore amount =A-P
=12321-10000
=2321
Hope it will help u plz mark me as a brainlist
Rate,r=11%
Time,n=2 years
=p(1+R/100)whole 2
=10000(1+11/100)whole 2
=10000(100+11/100)whole 2
=10000(111/100)whole 2
=10000*111/100*111/100
Now do cancelletion.
Zero will be cancelled
=1*111*111
=111*111
=12321
Therefore amount =A-P
=12321-10000
=2321
Hope it will help u plz mark me as a brainlist
Anirudhcharan1:
Thanks for this answer bro
Answered by
23
amount = p (1+r/100)^n
amount = 10000 (1+11/100)^2
amount = 10000 × 111/100 ×111/100
amount = 111×111 = 12321
compound interest = amount - principal
12321 - 10000 = 2321
hence compound interest = 2321
hope it helps you
amount = 10000 (1+11/100)^2
amount = 10000 × 111/100 ×111/100
amount = 111×111 = 12321
compound interest = amount - principal
12321 - 10000 = 2321
hence compound interest = 2321
hope it helps you
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