100000
Hence, price
In a mixture of three varieties of tea, the ratio of their weights is 4:5:8.15
ratio of the weights of three varieties of tea becomes 5:7:9. Find the quant
10 kg tea of the second variety and some quantity of tea of the third variety o
final mixture.
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Answer:
Let quantity of first variety of
tea = 4x kg.
Quantity of second variety of tea
= 5x kg.
Quantity of third variety of tea =
8x kg.
Let y kg of third variety of tea be
mixed.
Resultant ratio = (4x + 5) : (5x +
10) : (8x + y
∴
4
x
+
5
5
x
+
10
=
5
7
=> 28x + 35 = 25 x + 50
=> 28x – 25x = 50 – 35
=> 3x = 15
=> x = 5
∴
5
x
+
10
8
x
+
y
=
7
9
=> 40 + y = 9 × 5
=> y = 45 – 40 = 5 kg.
Required quantity of third variety
of tea
= 8x + y = 8 × 5 + 5 = 45 kg.
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