Question

1000a3+27b6 resolve into factor

Answer 1

(10a)^3 + (3b)^3

Using formula a^3+b^3= (a+b)(a² - ab + b²)

= (10a+3b) (100a^2-30ab+9b^2)

Answer 2

1000a³+27b⁶ = (10a)³+(3b²)³

= a³+b³=(a+b)(a²₋ab₊b²)

= (10a+3b²)(100a²-30ab²+9b⁴)