Question

(1001)³,Evaluate it using suitable identites.

Answer 1

hey mate here is your answer....

(1001)^3
(1000+1)^3
1000^3+3*1000^2*1+3*1000*1^2+1^3
1000000000+3*1000000+3*1000+1
1000000000+3000000+3000+1
ans-1003003001

Answer 2

Solution :

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We know the algebraic identity ,

( a + b )³ = a³ + 3a²b + 3ab² + b³

Or

( a + b )³ = a³ + b³ + 3ab( a + b )

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Now ,

( 1001 )³

= ( 1000 + 1 )³

= (1000)³ + 1³ + 3×1000×1(1000+1)

= 1000000000 + 1 + 3000×1001

= 1000000000 + 1 + 3003000

= 1003003001

Therefore ,

(1001)³ = 1003003001

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