Question

1008= n(48n-1) find the value of n
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Answer 1

Step-by-step explanation:

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Answer 2

$1008= n(48n-1)$

$1008= 48 {n}^{2} - n$

$- 48 {n}^{2} + n + 1008 = 0$

$- (48 {n}^{2} - n - 1008) = 0$

$48 {n}^{2} - n - 1008 = 0$

$n = \frac{ - b \: ± \sqrt{ {b}^{2} - 4ac} }{2a}$

$n = \frac{ - ( - 1) \: ± \sqrt{ {( - 1)}^{2} - 4 \times 48( - 1008)} }{2 \times 48}$

$n = \frac{ - 1 \: ± \sqrt{193537} }{96}$

$n = \frac{ 1 \: + \sqrt{193537} }{96}$

$n = \frac{ 1 \: - \sqrt{193537} }{96}$

$n = \frac{ - 1 \: ± \sqrt{193537} }{96}$