Question

100g of a solution of hydrochloric acid sp.gr.1.18
1.18) contains
36.5 g at the
the acid. The normality
of the solution is​

Answer 1

Given=

100g of Hcl solution

36.5 g of Hcl acid

Specific gravity =1.18

Density of solution= 1.1P×1g/ml

                              =1.18g/ml

Volume of Hcl solution=m/density

                                      = 100g/1.18g/ml

                                       =100/1.18 ml

nHcl= WHcl/MHcl

MHcl= 1+35.5

       =36.5g/mol

nHcl  = 36.5/36.5

nHcl = 1

Molarity = no. of mole of solute / v[L]

              =1/100/1.78×10⁻ ³

              =11.8

Normality =  m × no.factor

                = 1×11.8

Normality=11.8

Therefore, the normality of the solution is 11.8.

Answer 2

Given:- 100 g of hydrochloric solution.

36.5 g of HCL acid.

sp.gr=1.18

to find: normality of solution.

Explanation:

Density of solution = 1.18 × 1 gm/ml

= 1.18 gm/ml.

∴volume of HCL solution = mass / density.

= 100 gm / 1.18 gm/ml

= 100/1.18 ml.

∴ Mass of hcl= 1+35.5 = 36.5 g/mol

∴ n(hcl)=w(HCL)/M(HCL)

 = 36.5/36

 = 1

∴ Molarity = no of moles of solution / volume of solution in litres.

 =

=1.18 × 10

= 11.8 .

∴ Normality = m × n-factor

                    = 11.8 × 1

                     = 11.8 N.

Hence, The Normality of the solution is 11.8N.