Question

100g of Calcium carbonate reacts completely with 36.5g of hydrochloric acid. If the mass of gaseous products is 62 g, calculate the mass of residue formed​

Answer 1

Explanation:

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Answer 2

Answer:

The mass of residue is 74.5g

Explanation:

$CaCO_{3}$ + $HCl$ ⇒ $CaCl_{2}$ + $CO_{2}$ + $H_{2} O$

According to the law of conservation of mass,

mass of reactants = mass of products

Since gaseous product is carbon dioxide,

100g + 36.5g = $CaCl_{2}$ + 62g +

136.5g = 62g + residue

residue = 136.5g - 62g = 74.5g

∴ mass of residue = 74.5g