100g of ice at 0℃ is mixed with 100g of water at 80℃ . The resulting is 6℃. Calculate heat of ice
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heat of ice = mcΔT
= 100 x 0.5 x (6-0)
= 50 x 6 = 300 calories or 1260 joule
i hope it will help you
regards
= 100 x 0.5 x (6-0)
= 50 x 6 = 300 calories or 1260 joule
i hope it will help you
regards
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