Question

100g of ice is mixed with 100g of H2O at 100°C. The final temperature of the mixture is​

Answer 1

Answer:

13.33℃

Explanation:

Let the final temperature of the mixture be T.  

Then 100×80+100(T−0)×1/2100×80+100(T−0)×1/2  

(as specific heat of ice is 0.5cal/g/℃ and specific heat of water is 1cal/g∘C)  

=100×1×(100−T)

Solving, we get T=13.33℃

Answer 2

Answer:

T=13.33 degree C.............ANSWER..