Question

100g of impure sample of kclo3 on heating gives 24g of O2. 2kclo3 on heating gives 2kcl + 3o2...the percentage purity of kclo3 is​

Answer 1

Answer:

sorry I didn't know

but you can find it on Googl.e

have a great day tomorrow

Explanation:

please mark me as brainliest

Answer 2

Answer:

The percentage of purity of sample is 61.25%

Explanation:

Given:

Mass of impure sample of KClO3=100g

Mass of O2 after heating= 24g

Find:percentage purity of KClO3

step by step explanation:

Number of moles of O2= given mass/Molar mass

Number of moles of O2= 24/32=0.75mol

Chemical reaction:

If 2 moles of KClO3 gives 3 moles of O2

2KClO3→2KCl+ 3O2

Then ,2/3moles of KClO3 gives

2/3KClO3→2/3KCl+O2

•Therefore, 2/3 moles of KClO3 gives 1 mole of O2

Then,2/3*0.75moles of KClO3 gives 0.75mole of O2

That is ,

→2/3*0.75 mol KClO3→0.75mol of O2

→0.5 mol of KClO3→0.75mol of O2

Molar mass of KClO3=122.5g

Then the mass of KClO3= 0.5*122.5g=61.25g

percentage of purity of sample =

(61.25/100)*100

= 61.25%

So the percentage of purity of sample is 61.25%

#SPJ3