Question

100g of water at 70c is mixed with 60g of water at 30c ,what is the of mixture

Answer 1

Let’s say the final temperature of mixture is x and (20<x<40)

Now Simply Balance the Energy,

Energy Lost by the hot water=Energy Gain by the cold water

mass of hot water*c*(Temp. of hot water-x)=mass of cold water*c*(x-Temp. of cold water)

50*c*(40-x)=75*c*(x-20)

50*(40-x)=75*(x-20)

2*40–2*x=3*x-3*20

5*x=80+60

x=140/5

x=28

so, the final temperature of mixture is 28 degree Celsius

c: Specific Heat capacity of water

Answer 2

Answer:

55C°

Explanation:

100 ×70 + 60×30 = 160ΔT = 8800

ΔT =880/16 = 55C°