Question

100g of water is heated from 30°C to 50°C ignoring the slight expansion of the water , the change in its internal energy is ( specific heat of water is 4184J/Kg/K ) [AIEEE 2011]​

Answer 1

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Answer 2

Explanation:- As work done = 0

[∵ W = PΔV and ΔV = 0 , so W = 0)

Δ U = msΔT [given m= 100g = 100× 10⁻³ kg]

ΔU = 100 × 10⁻³ × 4184 × (50-30)

≈ 8.4KJ answer