Question

100J heat is generated in a resistance of 4ohm in 1 second.What is the potential difference of the resistor?​

Answer 1

Explanation:

$Heat \: Energy = {V}^{2}RT$

$= > H.E. = {V}^{2}RT$

$= > {V}^{2} = \frac{H.E.}{ RT}$

Here, H.E. (Heat Energy) = 100 J

, R (Resistance) = 4 ohm

& T (Time) = 1 sec

Substituting this values in the above formula:

${V}^{2} = \frac{100}{4}$

$= > {V}^{2} = 25$

$= > V = \sqrt{25}$

$= > V = 5 \: volt$

and,

that is the answer...

Answer 2

Explanation:

The produced heat is given as,

H=I

2

Rt

100=I

2

×4×1

I=25A

The potential difference is given as,

V=IR

=5×4

=20V

Thus, the potential difference across the resistor is 20V