Question

100J of work is done in tranferring 20 coulomb of charge between two points in a conductor find the resistance offered by the conductor if current is 2 ampere goes through it​

Answer 1

Explanation:

1. w=100j
2. Q=20
3. v=j/c=5
4. I=2A
5. R=V/I=5/2=2.5

Answer 2

Answer:

Work done on moving a charge 'q' across a potential difference 'ΔV'

is given by

W = qΔV ....... (1)

100J = 20C x ΔV ⇒ ΔV = 100J/20C = 5V

since charge goes through a potential drop of '5V'

i = ΔV/R

2A = 5V/R ⇒ R = 5V/2A = 2.5Ω

R = 2.5Ω is the resistance offered by the conductor