100m of a tower What is the height of the tower at a distance of 45 ° from the distance to its top?
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the hight will be 100M
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100m becoz tan45 = perpendicular÷ hypertenuse
tan45=1
so, 1= 100÷ x
x =100m
hope this help u
tan45=1
so, 1= 100÷ x
x =100m
hope this help u
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