100ml of 0.01N HCL is mixed with 200ml of 0.02 HCL .normality of resultant solution is
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N₁ = 0.01 N.
V₁ = 100 mL.
N₂ = 0.02 N
V₂ = 200 mL.
V = V₁ + V₂ = 100 + 200 = 300 mL.
Using Normality Equation,
NV = N₁V₁ + N₂V₂
∴ N × 300 = 0.01 × 100 + 0.02 × 200
⇒ 300 × N = 1 + 4
∴ N = 5/300
⇒ N = 0.0167 N.
Hence, the Normality of the Final Solution is 0.0167 N.
Hope it helps.
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