Question

100ml of 1M NaOH is mixed with 50ml of 1N KOH solution normality of mixture is

Answer 1

NV = N1V1 + N2V2

We know that N=n×M, where n is the no of equivalent so,

NV = n×M×V1 + N2V2

Putting the values,

N(100+50) = 1×1×100 + 1×50

150N=100 + 50

150N= 150

N=1

Answer 2

Answer:

Explanation:

Volume of Naoh = V1 = 100ml

Volume of KOH = V2 = 50ml

N1 = 1m and N2 = 1n

To calculate the normality of the solution after mixing 2 solutions, we use the equation:

NV=N1V1+N2V2/ V1+V2

Where N1V1 are the normality and volume of the NaOH.

and N2V2 are the normality and volume of the KOH.

Substituting values in the equation-

150 × N = n × M (100) + 1 × 1 (50) 150 × N

= 1 × 1 (100) + 50 N

= 150/150

= 1

Thus the normality of mixture is 1N.