Question

100ml of 20% alcohol solution in water is mixed with 200ml of 50% alcohol solution. Find the alcohol percentage in the new solution. ​

Answer 1

Answer:

The final solution is 10 liters

The 20% solution becomes 12%. 6x20/10

The 60% solution becomes 24%. 4x60/10

The total is then 36%. 12+24

Step-by-step explanation:

This solution contains of this liquid solute (alcohol) mixed with a liquid solvent (water), so we have to calculate the concentration of this solution in terms of volume percentage of solute (alcohol). (Now, we know that : <br> Concentration of solution

=("Volume of solute")/("Volume of solution ")xx100

<br> Here, Volume of solute (alcohol) = 50mL and Volume of solvent (water) = 150mL <br> So, Volume of solution = Volume of solute + Volume of Solvent <br>

=50+150

<br>

=200mL

<br> Now, putting these values of volume of solute and volume of solution in the the above formula we get : <br> Concentration of sodium

=(50)/(200)xx100 = (50)/(2) = 25 %

(by volume ) <br> Thus , the concentration of this alcohol solution is 25 per cent or that it is a 25% alcohol solution (by volume ).