Question

100ml of 9.8% h2so4 solute (d=1.1gm/ml) + 100ml of 19.6%H2so4 solute ( d=1.2gm/ml) so find Molarity in mixing. <br /><br /><br /><br />I think only the genius is given the explanation of this question
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Answer 1

Answer:

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This means 9.8g of sulphuric acid is present in solution

Explanation:

Answer 2

Answer:

1.75M

Explanation:

if 9.8% and 19.6% were w/w% of the solutions,

molarity of 1st solution =(%w/w ×d×10)÷GMW

=(9.8 × 10 × 1.1)÷98 =1.1M

molarity of the second =(19.6×10×1.2)÷98 = 2.4M

resultant molarity= (M1V1+M2V2)÷(V1+V2)

=(1.1×100 + 2.4×100)÷(100+100)

=(110+240)÷200 =350÷200 =1.75 M