100ml of a mixture of O2 and O3 are heated and O3 is 50% decomposed. The resultant mixture is
115ml. Find the initial volume of O3
(1) 55 ml
(2) 50 ml
(3) 65 ml
(4) 60 ml
Answers
Answered by
1
Explanation:
ANSWER
Ozone is highly soluble in turpentine. Thus, the decrease in volume of 20 ml is due to the solubility of ozone. Thus 100ml of a mixture contains 20 ml of ozone.
On heating, 20 ml of ozone decomposes to form 30 ml of oxygen. The net increase in volume will be (30−20)=10ml.
2O
3
→3O
2
So, the correct option is A
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