100ml of aqueous solution contain 6.023×10^21 solute molecules. Then solute is diluted to 1 lit. The number of solute molecules present in 10ml of dilute solution is
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Answer:
6×10^19
Explanation:
100 ml solution diluted to 1 liters (1000) ml contains 6.0×106^21solute molecular
No of molecules present in 10 ml
= 10×6.0×10^21 /1000
=6×10^19
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