. 100ml of ethylalcohol is made upto a
litre with distilled water. If the density of
C,H,OH is 0.46 gr/ml. then its molality is
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Answer:
10/9 m
Explanation:
Mass of ethanol = Volume × Density
= 100 ml × 0.46 g/ml
= 46 g
Moles of ethanol = Mass / Molar mass
= 46 g / (46 g/mol)
= 1 mol
Volume of water in the solution = 900 ml
Density of water = 1 g/ml
Mass of water = Volume × Density
= 900 ml × 1 g/ml
= 900 g
= 0.9 kg
Molality = Moles of solute / kg of solvent
= Moles of Ethanol / (kg of water)
= 1 mol / (0.9 kg)
= 10/9 m
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