Question

100pts


plz prove it

The tangent at the point of a circle is perpendicular to the radius through the point of contact .​

Answer 1

Given : A circle C (0, r) and a tangent l at point A.

To prove : OA ⊥ l

Construction : Take a point B, other than A, on the tangent l. Join OB. Suppose OB meets the circle in C.

Proof: We know that, among all line segment joining the point O to a point on l, the perpendicular is shortest to l.

OA = OC  (Radius of the same circle)

Now, OB = OC + BC.

∴ OB > OC

⇒ OB > OA

⇒ OA < OB

B is an arbitrary point on the tangent l. Thus, OA is shorter than any other line segment joining O to any point on l.

Here, OA ⊥ l

PLZ MARK AS BRAINLIST

FOLLOW ME

Answer 2

Given :

           A circle C (0, r) and a tangent l at point A.

To prove :

                 OA ⊥ l

Construction :

                       Take a point B, other than A, on the tangent l.

Join OB. Suppose OB meets the circle in C.

Proof:

            We know that, among all line segment joining the point O to a point on l, the perpendicular is shortest to l.

OA = OC  (Radius of the same circle)

Now, OB = OC + BC.

∴ OB > OC

⇒ OB > OA

⇒ OA < OBB is an arbitrary point on the tangent l.

Thus, OA is shorter than any other line segment joining O to any point on l.

Here, OA ⊥ l

Sry that iam not able to upload my pic !!

Hope this may help you and be the brainliest ..

keep smiling !^_^