100x^2-20x+1=0,find roots by factorization
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Answered by
16
Hey
Here is your answer,
100x^2 -20x + 1 = 0
100x^2 - 10x - 10x + 1. =0
10x(10x-1) - 1 (10x -1)=0
(10x -1)(10x -1)=0
10x -1=0
X=1/10
10x -1=0
X=1/10
Hope it helps you!
Here is your answer,
100x^2 -20x + 1 = 0
100x^2 - 10x - 10x + 1. =0
10x(10x-1) - 1 (10x -1)=0
(10x -1)(10x -1)=0
10x -1=0
X=1/10
10x -1=0
X=1/10
Hope it helps you!
Answered by
2
1 by 10, 1 by 10 are the roots of the factorization
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