100x^2 -20x +1 = 0 find the given quadratic equation using formula method and please note that the formula is
-b + or - root of b^2 - 4ac
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Correct question :-
Find the roots of the given quadratic equation : 100x² - 20x + 1 = 0.
Solution :-
100x² - 20x + 1 = 0
Comparing the given equation with ax² + bx + c = 0 we get,
- a = 100
- b = - 20
- c = 1
Discriminant D = b² - 4ac
⇒ D = ( - 20 )² - 4( 100 )( 1 )
⇒ D = 400 - 400
⇒ D = 0
Since b² - 4ac i.e, discriminant is equal to 0 therefore the given equation has 2 equal real roots
Now, using quadratic formula to find the roots
⇒ x = ( - b ± √D) /2a
Substituting the values
⇒ x = [ - ( - 20 ) ± √0 ] / 2( 100 )
⇒ x = (20 ± 0)/200
⇒ x = 20/200
⇒ x = 1/10
Therefore the roots of the given equation are 1/10 and 1/10.
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