100x + 99y = 5 and 99x + 100y = 3 . Find the values of x and y
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100x+99y=5 ----------------equetion (1)
99×+100y=3 ----------------eqution (2)
lets, be subtraction 1 from 2
100x+99y=5
-99x+100y=3
ans= 1x+ -1y= 2
so the eq 1x of cancelled and divide the ans of 2÷1
ans2therefore
x=2
putx=2 in eq no 1
100x+99y=5
100(2)+99y=5
200+99y=5
therefore (r.h.s) 5=200-99y
5=1y
5÷1
y=5
y=5
solution of equation is(x,y)=(2,5)
100x+99y=5 ----------------equetion (1)
99×+100y=3 ----------------eqution (2)
lets, be subtraction 1 from 2
100x+99y=5
-99x+100y=3
ans= 1x+ -1y= 2
so the eq 1x of cancelled and divide the ans of 2÷1
ans2therefore
x=2
putx=2 in eq no 1
100x+99y=5
100(2)+99y=5
200+99y=5
therefore (r.h.s) 5=200-99y
5=1y
5÷1
y=5
y=5
solution of equation is(x,y)=(2,5)
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