Question

100y^2-1 factorise using identity class 8

Answer 1

Answer:

(10y+1)(10y-1)

Step-by-step explanation:

100y^2-1

This can be written as.....

(10y)^2-(1)^2

By using the identity.....

(a)^2-(b)^2=(a+b)(a-b)

So.....

(10y+1)(10y-1)

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