Question

101. A box is placed on the floor of a truck moving
with an acceleration of 7 ms-2. If the
coefficient of kinetic friction between the box
and surface of the truck is 0.5, find the
acceleration of the box relative to the truck
1) 1.7ms 2
2) 2.1ms-2
2
3) 3.5ms- 4 ) 4.5ms-2​

Answer 1

Answer:

2.1 m/s^2

hope it is helpful

Answer 2

Answer:

2m/s

Explanation:

Find force acting on block

F= ma

Then find force between block and truck

f = umg ( u = 0.5 )

Then find F net

F net = F - f

Then find acceleration

$acc = \frac{f \: net}{m}$

Thank you