Question

101. Du An insulated Cup contains 75.0 g of water at 24.00 C. A 26.00 Sample of metal at 82. 25oC is added. The finas temperture of the water and metal is 28. 34 C. What is the specific heat of the metal?​

Answer 1

Answer:

Heat lost by the metal = Heat gained the

mass of water

Now,

Heat = mass*change in temperature*specific

heat capacity

Specific heat of water = 4.18 J/g. °C

Therefore,

75*4.18*(28.34-24) = 26*C*(82.25-28.34)

where C = Specific heat of the metal

C = (75*4.18*4.34)/(26*53.91) = 0.971 J/g.°C