Question

101
PHYSICS
CHEMISTRY
BIOLOGY
Question No.1
Water (density p) is flowing through the uniform tube of
cross-sectional area A with a constant speed as shown. The
magnitude of force exerted by the water on the curved
portion of the tube is
60°
à √3pAv?​

Answer 1

Given:

The angle of the curved surface = 60°

To find:

The magnitude of the force exerted by the water on the curved portion of the tube

Solution:

• We know that, ρAV² = k

• Also, F = √(k² + k² + 2k²x 1/2)       (As the angle of the curved part is 60°)

• Upon simplifying, F = k√3

                                         = √3ρAV²

• Thus, the magnitude of the force exerted by the water on the curved portion of the tube will be √3ρAV².

Answer 2

Answer:

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Explanation:

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