101. What volume of oxygen at 18°C and 750 torr, can be obtain from 110g of kclo3
a) 32.6L
b) 42.7L
c) 3.26 L
d)4.27L
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Acc. To me,
Your answer is a
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T=18°=291K
750torr=0.98atm
110/122.5=mole of kclo3
1mole kclo3--------------3 mole O2
110/122.5 mole------------3*110/122.5 mole O2
3*110/122.5 mole O2------------3/2*110/122.5 mole O
PV=nRT
0.98atm*V=3/2*110/122.5*0.0821*291
V=approx 32.4L
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I hope you understand my answer
I you think any mistake then comment me
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