Question

101. What volume of oxygen at 18°C and 750 torr, can be obtain from 110g of kclo3

a) 32.6L
b) 42.7L
c) 3.26 L
d)4.27L​

Answer 1

Acc. To me,

Your answer is   a

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T=18°=291K

750torr=0.98atm

110/122.5=mole of kclo3

1mole kclo3--------------3 mole O2

110/122.5 mole------------3*110/122.5 mole O2

3*110/122.5 mole O2------------3/2*110/122.5 mole O

PV=nRT

0.98atm*V=3/2*110/122.5*0.0821*291

V=approx 32.4L

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I hope you understand my answer

I you think any mistake then comment me

Answer 2

in this picture there is a answer of the above question

Explanation:

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