Question

102*101 Factorise

Mathematics Question​

Answer 1

Answer:

10301

Step-by-step explanation:

(102×101)=

(100+2)(100+1)

(100)^2+(1+2)100+1×2

10000+300+110301

(x+a(x+b)=x^2(a+b)x+a×b

a=2 b=1 x=100

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Answer 2

Step-by-step explanation:

101 and 102 can be written as (100+1) and (100+2) respectively.

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Identity =

$(x + a)(x + b) = {x}^{2} + x(a + b) + ab$

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When we substitute the value :

$(x + a)(x + b) = 100 {}^{2} + 100(1 + 2) + 1 \times 2 \\ = 10000 + 100 + 200 + 2 \\ = 10000 + 300 + 2 \\ = 10302$

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Verification :

By using calculations : 102*101 = 10302

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@ Lalitya