(102)^2 using suitable identity
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Answer:
(a+b)^2= a^2+b^2+2ab
(100+2)= (100)*2 + (2)*2 + 2(100)(2)
= 10000 + 4 + 400
= 10404
Step-by-step explanation:
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Answered by
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Answe
using the identity
(a+b)²=a²+b²+2ab
102 can be written as 100+2
where a=100 and b=2
a²+b²+2ab
100²+2²+2(100)(2)
10000+2+400
10404
therefore 102²=10404
hope it helps
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