Question

(102)³
find 102 cube by using cube identity.
(a+b)³
a³+3a²b+3ab²+b³
please answer fast​

Answer 1

Answer:

(102)3 =(100+2)3

(100)3+3(100)2(2)+3(100)(2)2+(2)3

=1000000+60000+1200+8=1061208

Answer 2

Answer:

Step-by-step explanation:

(100+2)^3=100^3+3×100^2×3+3×100×2^2+2^3

1061208