102. A ball is thrown with velocity of 10m/s at an
angle 50° with horizontal for a building of height
bm. It will strike ground after
A.2.7 sec
B. 2.4 sec C. 2.13 sec
D. 1.8 sec
Answers
Answered by
2
Answer:
Answer
Given,
u=30m/s
θ=30
0
t=1s
g=10m/s
2
Horizontal component of velocity along x-axis after 1s is
v
x
=u
x
+gt
v
x
=ucosθ+0×1
v
x
=30cos30
0
v
x
=25.98m/s
Vertical component of the velocity along y-axis after 1s is
v
y
=u
y
−gt
v
y
=30sin30
0
−10×1
v
y
=15−10
v
y
=5m/s
Velocity of a body after 1s is
v
=v
x
i
^
+v
y
j
^
v
=25.98
i
^
+5
j
^
Magnitude, v=∣
v
∣=
(25.98)
2
+(5)
2
v=
700
v=10
7
m/s
The correct option is A.
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