Question

102. If 5.6 g of KOH is dissolved in one I litre of water, its pH is (KOH = 56) b) 12 c) 11 d) 10 a a) 13​

Answer 1

Answer:

a ) 13

Explanation:

Molarity of KOH solution = =

Molecular weight×volume

Weight

=

56×1

5.6

=0.1 M.

This is equal to [OH

−

].

pOH=−log[OH

−

]=−log(0.1)=1

pH=14−pOH=14−1=13.

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Answer 2

Answer:

Correct option ()

Explanation:

Molarity of KOH solution = Weight/ Molecular weight×volume

                                 =5.6/56×1 =0.1 M.

This is equal to [OH−].

pOH=−log[OH−]=−log(0.1)=1

pH= 14−pOH = 14−1 = 13.

Hence, option  is correct.