102x 98 using identities
Answers
Answered by
18
=102×98
=(100+2)(100-2)
[USING (a+b)(a-b) =a²-b²]
=(100)²-(2)²
=10000-4
=9996
=(100+2)(100-2)
[USING (a+b)(a-b) =a²-b²]
=(100)²-(2)²
=10000-4
=9996
Anonymous:
thanks
Answered by
5
Hi ,
****************************
We know the algebraic identity
( a + b ) ( a - b ) = a² - b²
***********************************
Now ,
102 × 98
= ( 100 + 2 ) ( 100 - 2 )
By using above identity ,
= ( 100 )² - 2²
= 10000 - 4
= 9996
I hope this helps you.
: )
****************************
We know the algebraic identity
( a + b ) ( a - b ) = a² - b²
***********************************
Now ,
102 × 98
= ( 100 + 2 ) ( 100 - 2 )
By using above identity ,
= ( 100 )² - 2²
= 10000 - 4
= 9996
I hope this helps you.
: )
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