Question

103 cube find with identities​

Answer 1

Answer:

$(103 {)}^{3} \\ = (100 + 3 {)}^{3} \\ using \: \: this \: \: identity \: \\ (x + y {)}^{3} = {x}^{3} + {y}^{3} + 3xy(x + y) \\ (100 + 3 {)}^{3} = (100 {)}^{3} + (3 {)}^{3} + 3 \times 100 \times 3(100 + 3) \\ = 1000000 + 27 + 900(103) \\ = 1000000 + 27 + 92700 \\ = 1092727$

I hope it will help you

Answer 2

Answer:

(a+b)³ = a³+b³+ 3ab+ ab²..

hope it's help u

mark me as brainlist ✌️