Question

103. In a school 45% of the students play
cricket
, 30% play hockey and 15% play both.
Then the percentage of students who play nei-
ther cricket nor hockey is:
a) 50
b) 30
c) 60
d) 40​

Answer 1

Answer:

total =100%

so,(45+30+15)%= 90%

x+90%=100%

x=10%

so I think 10%

Answer 2

Answer:

60 percent%

Step-by-step explanation:

Given that, 45% play cricket; that is, P(C) = 45

100

= 9

20

30% play hockey; that is, P(H) = 30

100

= 6

20

And, 15% play both cricket and hockey; that is, P(CAnd H) = 15

100

= 3

20

Now, we have to find the probability that 1 student plays cricket or hockey;

That we have to find, P(C or H)

We know that, P(C or H) = P(C) + P(H) - P(C And H)

= 9/20 + 6/20 - 3/20

= 12/20

= 3/5

Hence, the required probability 3

5

so now convert fraction to percentage so, we will get the answer :60%

formula:

3/5×100% = 3/1×20% = 3×20% = 60%

please mark me. as Brainliest answer!!