Question

103 ka whole square by using identities a plus b ka whole square???​

Answer 1

Answer:

Answer. We can write 103 as 100+3 . By using the identity , (a+b)^2 = a^2+2ab +b^2. (100+3)^2 = 10000+9+600 = 10609.2

Answer 2

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$= > {(103)}^{2 } \\ => {(100 + 3)}^{2} \\ = > {(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab \\ = > {(100 + 3)}^{2} \\ = > {100}^{2 } + {3}^{2} + 2(100)(3) \\ = > 10000 + 9 + 600 \\ = > 10609$

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