103 multiplied by 107 with identities
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(100+3)(100+7)
(x+a)(x+b) = x^2 + (a+b)x + ab
(100)^2 + (3+7)100 + 3×7
10000 + 1000 +21 = 11021
(x+a)(x+b) = x^2 + (a+b)x + ab
(100)^2 + (3+7)100 + 3×7
10000 + 1000 +21 = 11021
gautam5894:
tq
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3
Its your answer it is well explained in image
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