Math, asked by Pha, 1 year ago

103 multiplied by 98 with using identities

Answers

Answered by kvnmurty
21
103 * 98 = (100 + 3) (100 -2 ) = 100² + 3*100  - 100 * 2 - 3 * 2
     = 10000 + 300 -200- 6
   = 10094

we use identity : (A+B)(A-C) = A^2 + AB - AC - BC
=============================
103 * 98 = (102 + 1) * 98 = 102 * 98 + 98
       = (100 + 2) (100 -2 )  + 98
       = 100² - 2² + 98
         = 10 094

Answered by saau
10
103*98 =(100+3) * (100-2) =(100)^2+(3-2)100+(3*-2) =10000+100-6 =10094
Similar questions