Question

104. An ocean liner leaves the harbour entrance travelling at 3 me and accelerates at 004 ms until it reaches its cruising speed of 15 ms How far does it travel in accelerating to its cruising speed b) 2.7 km C) 3 km d) 3.5 km a) 2.8 km

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Answer 1

Answer:

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We know that Diatance is given by second equation of motion , S=ut+

2

1

at

2

Here S=?=Distance

u=0= initial velocity

a=3m/s

2

= acceleratin

t=8s= time

So, using the equation we get

S=ut+

2

1

at

2

⇒S=0+

2

1

×3×8

2

⇒S=96m