Question

104 bata do plzzzzzzzzzzzzz​

Answer 1

Answer:

Hope it helps..............

Answer 2

Answer:

distance travelled is area under the velocity - time curve.

If you figure out the area OABCDE you'll get the distance

Area = Area(OAB)+Area(ABGH)+Area(BCFG)+Area(CDEF)

        = $[\frac{1}{2}*20*1] + [1*20]+[\frac{1}{2}*(20+10)*1] + [10*1] = 10+ 20+15+10 = 55m$

Distance travelled in 4s = 55m