104 g of water at 30°C is taken in a Calorimeter made of copper of mass 42 g.When a certain mass of ice at 0°C is added to it,the final steady temperature of the mixture after the ice has melted,was found to be 10°C.Find the mass of ice added.[Specific heat capacity of water=4.2 J/g*°C; Specific latent heat of fusion of ice=336J/g; Specific heat capacity of copper=0.4 J/g*°C]
Answers
Answered by
15
GIVEN
mass m1 of water is 104 grams
temperature of water t1 is 30 degree Celsius
temperature of calorimeter t2 is 30 degree Celsius
mass of calorimeter m2 is 42 gram
temperature of ice t3 is zero degree Celsius
let the mass of ice b x gram
total heat energy lost= (104×
mass m1 of water is 104 grams
temperature of water t1 is 30 degree Celsius
temperature of calorimeter t2 is 30 degree Celsius
mass of calorimeter m2 is 42 gram
temperature of ice t3 is zero degree Celsius
let the mass of ice b x gram
total heat energy lost= (104×
DwayneJohnson:
yes it is but please solve it.
actually during typing .....by mistake i pressed the answer option
total heat energy lost= (104×4.2×20)+(42×20×0.4)=8736+336=9072
total heat energy gained=(336×x)+(x×4.2×10)=336x+42x=378x
so according to the law of calorimetry:
378x=9072
x=9072/378=24
so your answer is, 24gram ice
Answered by
7
Answer:
Explanation:
C is the answer, I hope it will help you and please mark me as a brainliest
Attachments:
Similar questions