Question

(104) hole cube answer​

Answer 1

Answer:

${104}^{3} \\ = (100 + 4) ^{3} \\ since(a + b) ^{3} = {a}^{3} + {b}^{3} + 3a {b}^{2} + 3 {a}^{2} b \\ = {100}^{3} + {4}^{3} + 3 \times 100 \times {4}^{2} + 3 \times {100}^{2} \times 4 \\ = 1000000 + 64 + 19200 + 12000 \\ = 1124864$