104 kJ o work is dine on certain volume of gas. If the gas releases 125 kJ of heat, calculate the change in
internal energy (in kJ) of the gas.
Answers
Answered by
0
Answer:
-21kj
Explanation:
∆u =q+w
∆u=-125+104
∆u=-21kj
q is negative because heat released by the system
work is positive because work done by the system is taken as positive
Answered by
0
Answer:
21kJ
Explanation:
We know from 1st law of thermodynamics that
∆U= Q-W
Given:
W=104kJ
This is work done on gas
Hence we can write W=-104kJ
Simil,
Heat is released by gas and we write Q= -125kJ
Therefore,
From 1st lae of thermodynamics
∆U=|Q|-|W|
125-104
=21kJ
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